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(6x^2)/(x^2-4)=0
Domain of the equation: (x^2-4)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x^2!=4
x^2!=4/
x^2!=√1/0
x!=1
x∈R
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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